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(F)=-F^2-2F+15
We move all terms to the left:
(F)-(-F^2-2F+15)=0
We get rid of parentheses
F^2+2F+F-15=0
We add all the numbers together, and all the variables
F^2+3F-15=0
a = 1; b = 3; c = -15;
Δ = b2-4ac
Δ = 32-4·1·(-15)
Δ = 69
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$F_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$F_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$F_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(3)-\sqrt{69}}{2*1}=\frac{-3-\sqrt{69}}{2} $$F_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(3)+\sqrt{69}}{2*1}=\frac{-3+\sqrt{69}}{2} $
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